0.20=x^2/25-x

Solution for 0.20=x^2/25-x equation:

0.20=x^2/25-x

We move all terms to the left:

0.20-(x^2/25-x)=0


Domain of the equation: 25-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-25

x!=-25/1

x!=-25

x∈R


We add all the numbers together, and all the variables

-(x^2/25-x)+0.2=0

We get rid of parentheses

-x^2/25+x+0.2=0

We multiply all the terms by the denominator


-x^2+x*25+(0.2)*25=0

We add all the numbers together, and all the variables

-1x^2+x*25+5=0

Wy multiply elements

-1x^2+25x+5=0

a = -1; b = 25; c = +5;
Δ = b2-4ac
Δ = 252-4·(-1)·5
Δ = 645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{645}}{2*-1}=\frac{-25-\sqrt{645}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{645}}{2*-1}=\frac{-25+\sqrt{645}}{-2}
$